Question Bank - Computer Networks

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A certain population of ALOHA users manages to generate 70 request / sec. If the time is slotted in units of 50 msec, then channel load would be

A.
4.25
B.
3.5
C.
450
D.
350

Solution:

The correct answer is "option 2".CONCEPT:ALOHA is a multiple-access protocol for transmitting data in a shared medium.ALOHA is a communication method in which the source host sends the data to the destination host whenever the frame to be sent is available.ALOHA while sending frames does not check for a channel is busy or idle.CALCULATION:Channel load = number of request in 1-second ÷ number of slots in 1 secondNo. of requests - 70 requests/secOne time slot is of 50ms then the total number of time slots in 1 second ? \(\frac{1000ms}{50ms}\) ? 20 slotsChannel load = \(\frac{70}{20}\) = 3.5Hence, the correct answer is "option 2".Additional InformationThere are two types of ALOHA1. Pure ALOHA - In this, any station can transmit data at any time.2.Slotted ALOHA - In this ALOHA, any station can transmit data only at beginning of any time slot.

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