Question Bank - Computer Networks

Here's the question bank on all the computer networks topics.

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A network using CSMA / CD has a bandwidth 10 Mbps. If the maximum propagation time (including delays in the devices and ignoring the time needed to send a jamming signal) is 25.6 micro seconds. What is the minimum size of the frame?

A.
512 bytes
B.
1024 bytes
C.
64 bytes
D.
32 bytes

Solution:

Data:L = size of frameBW ? bandwidth = 10 Mbps = 10 × 106 b/sTp ? propagation time = 25.6 ?s = 25.6 × 10-6 sTt ? transmission timeFormula:For CSMA/CD,Tt ? 2 × Tp\({{\rm{T}}_{\rm{t}}} = \frac{{\rm{L}}}{{{\rm{BW}}}}\)Calculation:\(\frac{{\rm{L}}}{{{\rm{BW}}}} ? 2 × T_p\)L ? 2× Tp × BWL ? 2 × 25.6 × 10-6 × 10 × 106L ? 512 bitsL ? 64 × 8 bits // 8 Bit = 1 byteLmin = 64 bytesTherefore, the minimum size of a frame in the network is 64 bytes.

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