Here's the question bank on all the computer networks topics.
Consider an instance of TCPs Additive Increase Multiplicative Decrease (AIMD) algorithm where the window size at the start of the slow start phase is 2 MSS and the threshold at the start of the first transmission is 8 MSS. Assume that a timeout occurs during the fifth transmission. Find the congestion window size at the end of the tenth transmission.
The correct answer is option 3EXPLANATION:Initial window size or window size for first transmission: cwnd = 2 MSSFor 2nd transmission ? cwnd = 22 = 4 MSSFor 3rd transmission ? cwnd = 23 = 8 MSSWhen threshold is reached then additive increaseFor 4th transmission ? cwnd = 8 + 1 = 9 MSSFor 5th transmission ? cwnd = 9+ 1 = 10 MSS(fails)Now window size reduced to 10/2 =5 MSSFor 6th transmission ? cwnd = 1 MSSFor 7rd transmission ? cwnd = 21 = 2 MSSFor 8th transmission ? cwnd = 22 = 4 MSSThersoled reached now additive increaseFor 9th transmission ? cwnd = 4 + 1 = 5 MSSFor 10th transmission ? cwnd = 5 + 1 =6 MSSSo, at the end of 10th successful transmission The congestion window size will be 6 + 1 = 7 MSS
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