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A tourist boarded a train on 16.10.2021 from Udupi for Surat. The train departed from Udupi at 20:20 hours and reach Surat at 16:20 hours on the next day i.e., 17.10.2021. If the distance between the two city stations is 1080 km, the average speed of the train during the journey of the tourist was
Concept:Speed: The distance travelled by the body in unit time.\(Speed = \frac{{Distance}}{{Time}}\)Also, \(Time= \frac{{Distance}}{{Speed}}\)Average Speed: Since the body does not always have the same speed, So we use the concept of average speed. It is the ratio of total distance covered to total time taken by the body.\(Average\;Speed = \frac{{Total\;Distance}}{{Total\;Time}}\)Conversion of units of speed:From km/hr to m/s = multiply by 5/18From m/s to km/hr = multiply by 18/5Calculation:StationDateArrivalDepartureUdupi16.10.2021-20:20Surat17.10.202116:20-Total Distance covered = 1080 KmTime taken = 20 hrsAverage Speed = distance/ time = (1080/20) = 54 km/hSince the options are in m/s so,54 À” (5/18) = 15 m/sThus, average speed of the train is 15 m/s. Mistake PointsDo not confuse with units Km/hr and m/sConversion of units of speed:From km/hr to m/s = multiply by 5/18From m/s to km/hr = multiply by 18/5
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