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A husband and wife appear in an interview for two vacancies for the same post. The probability of husband getting selected is 1/5 while the probability of wife getting selected is 1/7. Then the probability that any one of them getting selected is

A.
Nov-35
B.
Dec-35
C.
Jan-35
D.
34/35

Solution:

The probability of husband getting selected is 1/5 and the probability of wife getting selected is 1/7.Now, the converse of the statement that œany one of them getting selected is œnone of them getting selected \(\left( {1 - \frac{1}{5}} \right).\left( {1 - \frac{1}{7}} \right)\frac{4}{5}.\frac{6}{7} = \;\frac{{24}}{{35}}\)The probability of none them getting selected = (Probability of husband not getting selected). (Probability of wife not getting selected) = =Hence, the probability that any one of them getting selected = 1 - probability of none them getting selected = \(- \frac{{24}}{{35}} = \frac{{11}}{{35}}\)

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