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? and ? are two operators on numbers p and q such that \(p \oplus q=\frac{p^2+q^2}{pq}\) and \(p \odot q =\frac{p^2}{q};\) If x ? y = 2 ? 2, then, x =
Given:\(p \oplus q=\frac{p^2+q^2}{pq}\)\(p \odot q =\frac{p^2}{q};\)Calculation:LHS = x ? y = \(\frac{x^2+y^2}{xy}\)RHS = 2 ? 2 = 22/2 = 2? 2 ? 2 = 2\(\frac{x^2+y^2}{xy} = 2\)? x2 + y2 = 2xy? x2 + y2 “ 2xy = 0? (x “ y)2 = 0Thus,x = y
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