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An element 'X' is present in 15th group and 3rd period of periodic table. If the mass number of an isotope of this element is 33, what is the number of neutrons present in an atom of that isotope?

A.
18
B.
15
C.
13
D.
20

Solution:

The correct answer is 18.Concept:Atomic number: The number of electrons or protons in an atom.Mass number: The number of protons and neutrons taken together.Isotopes: The elements with the same atomic number but different mass numbers due to the different numbers of neutrons.Explanation:Group number: It tells how many valence electrons are present in the outermost shell of the atom.Element X has group number 15. So, the no. of valence electrons is 15-10 = 5.Period number: It tells how many shells are there in the atom. Element X belongs to the 3rd period. So, there are 3 shells. Electronic configuration of Element X = 2, 8, 5.Its atomic number is 15. Therefore, there are 15 electrons and 15 protons in it. The mass number of its isotope is 33.No. of neutons + no. of protons = 33No. of neutons + 15 = 33No. of neutrons = 33 - 15 = 18

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