Here's the question bank on all the general science topics.
An object, 1.0 cm in height, is placed at a distance of 15.0 cm in front of a concave mirror of focal length 30.0 cm, on its principal axis. Following New Cartesian Sign Convention, the image is formed at v = _________ and its height hI = ________.
The correct answer is 30 cm; 2.0 cm.Concept:Mirror formula:\(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\), where f = focal length, v = image distance and u = object distance.Magnification: m = \(\frac{Hi}{Ho} = \frac{-v}{u}\) , where Hi = height of image, Ho = height of object, v = image distance, and u = object distance.Concave mirror: It is part of a whole spherical mirror that reflects light from the hollow part.It is a converging mirror because it converges the incident rays at a point.Explanation:Given, u = -15 cm f = -30 cm h = 1 cm \(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\)\(\frac{1}{-30} = \frac{1}{v} + \frac{1}{-15}\)\(\frac{1}{-30} = \frac{1}{v} - \frac{1}{15}\)\(\frac{1}{v} = \frac{1}{-30} + \frac{1}{15} \)\(\frac{1}{v} = \frac{-1 + 2}{30} \)\(\frac{1}{v} = \frac{1}{30} \)v = 30 cmm = \(\frac{Hi}{Ho} = \frac{-v}{u}\) = \(\frac{Hi}{2} = \frac{-(30)}{-15}\) Hi = 2 cmFollowing New Cartesian Sign Convention, the image is formed at v = 30 cm and its height HI = 2 cm.
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