Question Bank - General Science

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How many molecules of water are present in a drop of water weighing 10 g?

A.
0.33 À” 1024
B.
0.177 Ãƒ€” 1024
C.
1.08 À” 1024
D.
6.022 À” 1023

Solution:

The correct answer is 0.33 À” 1024 .Concept:Mole:It is the SI unit of the amount of substance.One mole contains exactly 6.022À”1023 atoms/molecules. The mass of one mole of a substance in grams is called its molar mass.The molar mass in grams is numerically equal to atomic/molecular/formula mass in u.So, 1 mole = 6.022 À” 1023 atoms/molecules = Atomic/molecular mass of an element/compound.Explanation:Molar mass of water (H2O) = 2 À” 1 + 16 = 18g1 mole of water = molar mass of water = 6.022 À” 1023 molecules of water18 g of water = 6.022 À” 1023 molecules of water1 g of water = 6.022 À” 1023 / 18 molecules of water10 g of water = 6.022 À” 1023 À” 10 / 18 molecules of water = 0.33 À” 1024 molecules of water

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