Here's the question bank on all the logical reasoning topics.
If 2 men or, 6 women or, 4 boys can finish a work in 88 days, then how many days will 1 man, 1 woman and 1 boy together take to finish the same work?
FORMULA:Total work = Time × EfficiencyGiven:Total time taken = 88 days2 Men = 6 Women = 4 BoysCalculation:Let, Efficiency of Men = M, Efficiency of Women = W, Efficiency of Boy = B2M = 6W = 4B = K ? (i)K = L.C.M of 2, 6 and 4 ?K = 12From (i)2M = 12 ? M = 66W = 12 ? W = 24B = 12 ? B = 3Total work done is 2M × 88 = 2 × 6 × 88 Total efficiency of 1 man, 1 woman and 1 boy = 1M + 1W + 1B = 6 + 2 + 3 = 11Therefore, total time taken by 1 man, 1 woman and 1 boy= (Total work) ÷ (Total efficiency)= (2 × 6 × 88 ) / 11= 2 × 6 × 8 = 96 days.Hence, the correct answer is "96 days".
Scan QR code to download our App for
more exam-oriented questions
OR
To get link to download app