Here's the question bank on all the mathematics topics.
A straight line passes through the point of intersection of x + 2y + 2 = 0 and 2x - 3y - 3 = 0. It cuts equal intercepts in the fourth quadrant. What is the sum of the absolute values of the intercepts?
Concept:A positive slope means y increases as x increases (visually, the line moves up as you go from left to right).A negative slope means y decreases as x increases (visually, the line moves down as you go from left to right).Calculation:Given:x + 2y + 2 = 0 ------(i)2x - 3y - 3 = 0 ------(ii)By solving (i) and (ii) we get the point of intersection of the lines.So x = 0 and y = -1The point of intersection is (0, -1)Given that the line makes equal intercepts with axes. So slope (m) can be tan ? = 1or -1 but it is in the fourth quadrant so, it is positive.Then the equation of the line is y - y1 = m(x - x1)? y - (-1) = 1(x - 0)? y + 1 = x? x - y = 1From this equation, the intercept on the x and y axes are 1 and -1 respectively.? The sum of the absolute values of the intercepts = 2.
Scan QR code to download our App for
more exam-oriented questions
OR
To get link to download app