Concept:1). The area of the triangle formed by three vertices that are collinear is zero.2). Area of a triangle formed by (x1šÃ„ã,y1šÃ„ã), (x2šÃ„ã,y2šÃ„ã), and (x3šÃ„ã,y3šÃ„ã) is given by, Area = \(\displaystyle \frac{1}{2}\)šÃ„ã[x1šÃ„ã(y2 šÃ„ã- y3šÃ„ã) + x2šÃ„ã(y3 šÃ„ã? y1šÃ„ã) + x3šÃ„ã(y1 šÃ„ã? y2šÃ„ã)]Calculation:Given,Points with coordinates (-5, 0), (5p2, 10p) and (5q2, 10q) are collinear? Area of šÃ±?ABC=0We know that,Area of a triangle formed by (x1šÃ„ã,y1šÃ„ã), (x2šÃ„ã,y2šÃ„ã), and (x3šÃ„ã,y3šÃ„ã) is given by,Area = \(\displaystyle \frac{1}{2}\)šÃ„ã[x1šÃ„ã(y2 šÃ„ã- y3šÃ„ã) + x2šÃ„ã(y3 šÃ„ã? y1šÃ„ã) + x3šÃ„ã(y1 šÃ„ã? y2šÃ„ã)]? Area of šÃ±?ABC = \(\displaystyle \frac{1}{2}\)[-5(10p ? 10q) + 5p2(10q ? 0) + 5q2(0 ? 10p)]? 0 = -50p + 50q + 50p2q - 50q2p? 0 = 50(q - p) + 50(p2q - q2p)? 50(q - p) = 50(p2q - q2p)(q - p) = (p2q - q2p)(q - p) = pq(q - p)? pq = 1 [p ? q]? The value of pq = 1