Question Bank - Mathematics

Here's the question bank on all the mathematics topics.

Let \(\vec{a}, \vec{b}, \vec{c}\) be three non-zero vectors such that \(\vec{a}\times \vec{b} = \vec{c} \). Consider the following statements:1. \(\vec a\) is unique if \(\vec b\) and \(\vec c\) are given2. \(\vec c\) is unique if \(\vec a\) and \(\vec b\) are givenWhich of the above statements is/are correct?

A.
1 only
B.
2 only
C.
Both 1 and 2
D.
Neither 1 nor 2

Solution:

Concept:Properties of the cross product of vectora × b is a vector that is perpendicular to both a and b.The direction of a × b is determined by the right-hand rule. (This means that if we curl the fingers of the right hand from a to b, then the thumb points in the direction of (a × b)).The magnitude (or length) of the vector a × b, written as ?a × b?b × a = ? a × b and a × a = 0Calculation:Statement I: \(\vec a\) is unique if \(\vec b\) and \(\vec c\) are givenIf \(\displaystyle \vec b\ and \ \vec c\) are given, then vector a is determined by the right-hand rule which is perpendicular to both \(\displaystyle \vec b\ and \ \vec c\)As \(\displaystyle \vec b\ and \ \vec c\) is given, the magnitude of \(\displaystyle \vec b\ and \ \vec c\) is also given.So, we can say that \(\displaystyle \vec a\) is unique whose magnitude and direction are dependent on \(\displaystyle \vec b\ and \ \vec c\)Thus, a statement I is correct.Statement II: \(\vec c\) is unique if \(\vec a\) and \(\vec b\) are givenIf \(\displaystyle \vec a\ and \ \ \vec b\) are known then the resultant is perpendicular to both a and b which is given the right-hand rule.The magnitude of the vector a × b, written as ?a × b?. As a and b are given, magnitude is unique.So, we can say that \(\displaystyle \vec c\) is unique whose magnitude and direction are dependent on \(\displaystyle \vec a \ and \ \vec b\)Thus, statement II is correct.? Both statements I and II are correct.

For more questions,

Click Here

Download Gyanm App

free current affairs for competitive exams

Scan QR code to download our App for
more exam-oriented questions

free current affairs for competitive exams

OR
To get link to download app

Thank you! Your submission has been received. You will get the pdf soon. Call us if you have any question: 9117343434
Oops! Something went wrong while submitting the form.