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The number of likes on the last four photos posted on Facebook is 3, 15, 21, and 13. The mean absolute deviation value about the mean of likes is:
GivenThe number of likes on the last four photos posted on Facebook is 3, 15, 21, and 13GormulaMean = ?xi/nAbsolute mean deviation = 1/n(?I xi “ x?)CalculationMean = x? = (3 + 15 + 21 + 13)/4? x? = 13Mean about absolute deviation = 1/4(I 3 “ 13 I + I 15 “ 13 I + I 21 “ 13 I + I 13 “ 13I? 1/4(10 + 2 + 8 + 0)? 1/4( 20)? Mean about absolute deviation is 5
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