Formula used:Probability of occurrence of the event:P(E) = \(\frac{n(E)}{n(S)}\)Where,n(E) = Number of favorable outcomen(S) = Number of possible outcomeCalculation:Let, G be the event that the first applicant interviewed is a graduate.T be the event that the first applicant interviewed has at least 3 years of experience.G? is the event that the first applicant interviewed is not a graduateT? is the event that the first applicant interviewed has less than three years of experienceNow, from the table we have,Number of applicants who are graduates and have less than three years of experience, \(n (G \cap \overline T)\) = 36Total number of applicants n(S) = 90So the required probability is given by\(P (G \cap \overline T)\) = \(\displaystyle \frac{n (G \cap \overline T)}{n(S)}\) = \(\displaystyle \frac{36}{90}=\frac{2}{5}\)\(P (G \cap \overline T)\) equal to \(\displaystyle \frac{2}{5}\).