Concept:Probability of occurrence of the event:P(E) = \(\frac{n(E)}{n(S)}\)Where,n(E) = Number of favorable outcomen(S) = Number of possible outcomeConditional probability:of two events is given by P(A|B) = \(\displaystyle \frac{n (A \cap B)}{n(B)}\)P(A|B) represents the probability of occurrence of A given B has occurred.Calculation:Let, G be the event that the first applicant interviewed is a graduate.T be the event that the first applicant interviewed has at least 3 years of experience.G? is the event that the first applicant interviewed is not a graduateT? is the event that the first applicant interviewed has less than three years of experienceNow, from the table we have,Number of applicants having less than three years of experience, \(n (\overline T)\) = 36 + 27 = 63Total number of applicants, n(S) = 90Now, \(\displaystyle P(\overline T)=\frac{n(\overline T)}{n(S)}=\frac{63}{90}=\frac{7}{10}\)So the required probability is given by:\(P(G | \overline T) \) = \(\displaystyle \frac{P (G \cap \overline T)}{P(\overline T)}\) = \(\displaystyle \frac{\frac{2}{5}}{\frac{7}{10}}=\frac{4}{7}\)\(P(G | \overline T) \) equal to \(\displaystyle \frac{4}{7}\).