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A message consisting of 2400 bits is to be passed over the Internet. The message is passed to the transport layer which appends a 150-bit header, followed by the network layer which uses a 120-bit header. Network layer packets are transmitted via two networks, each of which uses a 26-bit header. The destination network only accepts up to 900 bits long. The number of bits, including headers delivered to the destination network, is
Given:Message size = 2400 bits.The header of the transport layer = 150 bits.Segment size at transport layer = (Header + Message size) = 150 + 2400 = 2550 bits.Maximum, transmission unit at destination network = 900 bits So, At a time, data supported by the destination network = 900 “ 26 = 876 bits.Hence, 2550 bits are divided into packets having a maximum of 876 bits. So:Length of packet 1 = 874 bits.Length of packet 2 = 874 bits.Length of packet 3 = 802 bits.Total = 2550 bits.Network layer packets are transmitted via two networks, each of which uses a 26-bit header. So, The number of bits, including headers delivered to the destination network is:Packet 1 (Data + Header) size = 26 + 26 + 874 = 926 bits.Packet 2 (Data + Header) size = 26 + 26 + 874 = 926 bits.Packet 3 (Delta + Header) size = 26 + 26 + 802 = 854 bits. Total = 2706 bits.
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