Question Bank - Computer Networks

Here's the question bank on all the computer networks topics.

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Consider a CIDR network address 194.24.0.0/21. The last address in this network will be:

A.
194.24.7.255
B.
194.24.11.255
C.
194.23.7.255
D.
194.24.7.250

Solution:

Here, no. of mask bits = network id = n = 21In classless addressing, no. of address are given by 232-nFor last address set 32 “ n rightmost bits to 1. i.e. set 11 rightmost bits to 1.194.24.0000 0000. 0000 0000194.24.0000 0111. 1111 1111The last address in this network will be 194.24.7.255

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