Question Bank - Computer Networks

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Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s.

A.
1
B.
2
C.
2.5
D.
5

Solution:

Data:Length of packet = L = 10,000 bitsBandwidth = BW = 500 Mbps = 500 × 106 bpsVelocity = V = 2,00,000 km/s = 2 × 105 km/sd ? length of cableTp ? propagation timeTt ? transmission timeFormula:For CSMA/CD,\({T_t} \ge 2 \times {T_p}\)\(\frac{L}{{BW}} \ge 2 \times \frac{d}{V}\)\(d \le \frac{{L \times V}}{{2 \times BW}}\)Calculation:\(d \le \frac{{10,000 \times 2 \times {{10}^5}\;}}{{2 \times 500\; \times {\rm{\;}}{{10}^6}}}\)\(\;d \le 2\;km\)\({d_{max}} = \;2\;km\)

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