Question Bank - Computer Networks

Here's the question bank on all the computer networks topics.

In a token ring network, the transmission speed is 107 bps and the propagation speed is 200 m/?s. Then 1 bit delay in this network is equivalent to

A.
500 m of cable
B.
200 m of cable
C.
20 m of cable
D.
50 in of cable

Solution:

Data:Transmission speed = Tt =107 bpsPropagation speed = Tp = 200 m/?s.Length = 1 bitFormula\({T_t} = \frac{L}{{BW}}\)\({T_p} = \frac{d}{v}\)Calculation:Tp = 200 m/?s. In 1-sec distance covered 200×106 meter1 bit delay = (1 ÷ BW) × v = (1 ÷ 107 )× 200×106 = 20 meters cable

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