Here's the question bank on all the computer networks topics.
Suppose we want to download-text documents at the rate of 100 pages per second. Assume that a page consists of an average of 24 lines with 80 characters in each line. What is the required bit rate of the channel?
The correct answer is "option 4".CONCEPT: Bit rate means no. of bits per second.Data: Download rate: 100 pages/secondNo. of lines per page: 24 lines/pageNo. of characters per line: 24 character/lineFormula:Bit rate of channel = No. of pages/second × No. of lines/page × No. of characters/line × No. of bitsCALCULATION: Bit rate of channel = 100 pages × 24 lines × 80 characters × 8 bits = 1536000 bits/second or 1.536MbpsHence, the bit rate is 1.536Mbps.Mistake Points Never consider Mbps & MBPS as the same. Mbps - Mega Bits Per SecondMBPS - MegaBytes Per Second1 Byte - 8 bits
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