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A boy boarded a train on 4th June, 2020 at Nagarcoil for Madgaon. The train departed at 22:30 hours from Nagarcoil and reached Madgaon at 04:30 hours on 6th June, 2020. If the distance covered by the train during this time interval is 1145 km, the average speed of the train was nearly

A.
38.5 km/h
B.
40.5 km/h
C.
42.5 km/h
D.
36.5 km/h

Solution:

Concept:Speed: The distance travelled by the body in unit time.\(Speed = \frac{{Distance}}{{Time}}\)Also, \(Time= \frac{{Distance}}{{Speed}}\)Average Speed: Since the body does not always have the same speed, So we use the concept of average speed. It is the ratio of total distance covered to total time taken by the body.\(Average\;Speed = \frac{{Total\;Distance}}{{Total\;Time}}\)Calculation:StationDateArrivalDepartureNagarcoil4th June 20-22:30Madgaon6th June, 2004:30- Total distance = 1145 kmTotal time taken = 1.5 hr + 24 hr + 4.5 hr = 30 hrWe know that,\(Average\;Speed = \frac{{Total\;Distance}}{{Total\;Time}}\)\(? Average\;Speed = \frac{{1145\;km}}{{30\;hr}}\)? Average Speed = 38.16 km/hrThe average speed of the train was nearly 38.5 km/hr

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