Given digits: 2, 2, 3, 3, 3, 4, 4, 4, 4Case 1:The first digit is 4.4 _ _ _Rest of the places are filled by 2, 2, 3, 3, 3, 4, 4, 4\( \Rightarrow \begin{array}{*{20}{c}} 4&\_&\_&\_\\ \downarrow & \downarrow & \downarrow & \downarrow \\ 1&3&3&3 \end{array}\)The no. of cases = 1 × 3 × 3 × 3 “ 1 = 26Case 2:The first digit is 3:Rest of the places are filled by 2, 2, 3, 3, 4, 4, 4, 4The exception cases are = 222, 333Therefore:\(\begin{array}{*{20}{c}} 3&\_&\_&\_\\ \downarrow & \downarrow & \downarrow & \downarrow \\ 1&3&3&3 \end{array}\)No. of cases = 1 × 3 × 3 × 3 “ 2= 25Case 3:First digit is 2No number can be possible which is greater than 3000Total no. of cases = 26 + 25 = 51