Question Bank - General Aptitude

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The following figure shows the data of students enrolled in 5 years (2014 to 2018) for two schools P and Q. During this period, the ratio of the average number of the students enrolled in school P to the average of the difference of the number of students enrolled in schools P and Q is ______

A.
08:13
B.
23:08
C.
23:31
D.
31:23:00

Solution:

The average number of students enrolled in P will be:\({A_p} = \frac{{3k\; + \;5k \;+ \;5k \;+\; 6k\; + \;4k}}{5}\)Ap = 4600Similarly, The average number of students enrolled in Q will be:\({A_Q} = \frac{{4k\; +\; 7k \;+\; 8k \;+ \;7k\; + \;5k}}{5}\)AQ = 6200Average of the difference in the number of students enrolled in P and Q will be:= AQ - Ap= 6200 “ 4600= 2600The required ratio will now be:\(= \frac{{{A_p}}}{{{A_Q} - {A_p}}}\)\(= \frac{{4600}}{{6200 - 4600}} = \frac{{46}}{{16}}\)= 23 : 8

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