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The number of minutes spent by two students, X and Y, exercising every day in a given week are shown in the bar chart above. The number of days in the given week in which one of the students spent a minimum of 10% more than the other student, on a given day, is
Concept:Here it is asked to calculate cases where the percentage is greater than 10%, so we must ensure that the denominator here is the lowest among the two on a given day.Calculation:Given:The percentage of time spent by one student than the other is:On Sunday = \(\frac{65\ -\ 55}{55}\ \times\ 100\) = 18.18%On Monday = \(\frac{70\ -\ 45}{45}\ \times\ 100\) = 55.55%On Tuesday = \(\frac{65\ -\ 55}{55}\ \times\ 100\) = 18.18%On Wednesday = \(\frac{60\ -\ 50}{50}\ \times\ 100\) = 20%On Thursday = \(\frac{60\ -\ 55}{55}\ \times\ 100\) = 9.09%On Friday = \(\frac{35\ -\ 20}{20}\ \times\ 100\) = 75%On Saturday = \(\frac{60\ -\ 50}{50}\ \times\ 100\) = 20%From the above-calculated data, 6 days are there where one student spend a minimum of 10% more than the other student.Download Solution PDFShare on Whatsapp
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