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The refractive index of glass (dense flint) and turpentine oil is 1.65 and 1.47, respectively. A ray of light travels from turpentine oil to glass. The refractive index of glass with respect to turpentine oil is ________ and the light ray bends _______ the normal in glass.

A.
0.89, away from
B.
1.12, away from
C.
0.89, towards
D.
1.12, towards

Solution:

The correct answer is 1.12; towards.Concept:Refraction of Light: The bending of the ray of light passing from one medium to the other medium is called refraction.Refractive Index (n): n = sin i / sin r, where 'i' = angle of incidence and 'r' = angle of refraction. Also, n = c/v, where c = speed of light in a vacuum, and v = speed of light in a medium.Explanation:?Relative refractive index:It refers to the refractive index of one material medium with respect to another one.\(n_{21}= \frac{n_{2}}{n_{1}}\)Refractive index of glass (dense flint) with respect to turpentine oil:\(n= \frac{Refractive \ index \ of \ glass (dense flint)}{Refractiev \ index\ of\ Turpentine \ oil}= \frac{1.65}{1.47}=1.12\)Greater the refractive index, the denser the medium.Thus, glass (1.65) is denser than turpentine oil (1.47).When the ray of light moves from a denser to a rarer medium, the refracted ray moves away from the normal.When the ray of light moves from a rarer to a denser medium, the refracted ray moves towards the normal.Thus, when a light ray will move from turpentine oil to glass, it will move towards the normal.The refractive index of glass (dense flint) with respect to turpentine oil is 1.12 and the light ray bends towards the normal in the glass.

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