Question Bank - Mathematics

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Evaluate: ?e5 log x dx

A.
6 log x + C
B.
e6 + C
C.
x6/6 + C
D.
x5/5 + ex + C

Solution:

Concept Used:1. a logx = log (xa)2. elog(n) = n3. ?xndx = \(\frac{x^{n+1}}{n+1}+C\)Application:We have,I = e5 log xor, I = \(e^{log(x^5)}\) = x5Hence, ?x5 dx = x6/6 + C

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