Question Bank - Mathematics

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Evaluate ? (e5x - 2x )dx

A.
\(\rm {e^{5x} \over5} + {2^x\over lnx} + C\)
B.
\(\rm {e^{5x} \over5} - {2^x\over ln2} + C\)
C.
\(\rm {e^{5x} \over5} + {2^x\over ln2} + C\)
D.
\(\rm -{e^{5x} \over5} - {2^x\over ln2} + C\)

Solution:

Concept:Some useful formulas are: ? eax dx = \(\rm e^{ax} \over a\) + C ? ax dx = \(\rm {a^{x} \over ln \ a} + C\), a > 0 and a ? 1Calculation: ? (e5x - 2x )dx= ? e5x dx - ? 2x dx= \(\rm {e^{5x} \over5} - {2^x\over ln2} + C\), where C is the constant of integration

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