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If log10 [98 + ?(2x2 - 25x + 76)] = 2, then the value of x:

A.
09-Feb
B.
8
C.
9/2, 8
D.
9/2, 2

Solution:

CONCEPT:If log a (x) = b ? x = ab CALCULATION:As log10 [98 + ?(2x2 - 25x + 76)] = 2? [98 + ?(2x2 - 25x + 76)] = 102? ?(2x2 - 25x + 76) = 100 - 98? ?(2x2 - 25x + 76) = 2Squaring both sides, we get? [?(2x2 - 25x + 76)]2 = (2)2 ? 2x2 - 25x + 76 = 4? 2x2 - 25x + 76 - 4 = 0? 2x2 - 25x + 72 = 0? 2x2 - 16x - 9x + 72 = 0? 2x(x - 8) - 9 (x - 8) = 0? (2x - 9) (x - 8) = 0? 2x - 9 = 0 or x - 8 = 0? x = 9/2 or x = 8 ? x = 9/2, 8 The quadratic equation always has 2 roots. Hence, Option 1 and 2 will be eliminated as both of them give only one value as the root of the quadratic equation. After obtaining the quadratic equation 2x2 - 25x + 72 = 0 from the given logarithmic equation, check by substituting the values from options 3 and 4 in the obtained quadratic equation.

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