Question Bank - Mathematics

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The chance that a software engineer will debug an error X correctly is 80%. The chance that software with the error X will crash after the correct debugging is 30%. The chance of crash of the software by wrong debugging is 70%. A software with the error X crashed. The probability that its error was debugged correctly is:

A.
\(\dfrac{7}{12}\)
B.
\(??\dfrac{7}{19}\)
C.
\(??\dfrac{6}{19}\)
D.
\(??\dfrac{12}{19}\)

Solution:

GivenP(A I B) = 30% = 0.3P(A) = 80% = 0.8P(B I A) = 70% = 0.7P(A) = 100% - 80% = 2-0% = 0.2FormulaP(A I B) = P(A I B). P(A)/P(B) = [P(A I B). P(A)]/[P(A I B). P(A) + P(B I A) P(A)]CalculationP(A I B) = (0.3 × 0.8)/(0.3 × 0.8 + 0.7 + 0.2)? 0.24/(0.24 + 0.14)? 0.24/0.38? The probability that its error was debugged correctly is 12/19

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