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The horizontal distance between two towers is 100 m and the angular depression of the top of the first tower as seen from the top of the second tower, which is 120 m high, is 45°. Find the height of the first tower.
Given:Distance between two towers = 100 mHeight of second tower = 120 mAngular depression = 45° Formula Used:Tan ? = H/BWhere, H = HypotenuseB = baseCalculation:Let the length of first tower (CD) be h ? AE = AB - EB? AE = 120 - hIn the above figureBC = ED = 100mAccording to the question, we haveIn ?AED,Tan 45° = AE/ED? 1 = (120 - h)/100? 100 = 120 - h? h = 120 - 100? h = 20 m? The length of the first tower is 20 m.
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